What is the divisible of 1125?
Divisibility of 1125 The number 1,125 is divisible by 3, 5 and 9.
What Can 1470 be divided by?
For 1470, all of the possible factor pairs are listed below:
- 1 x 1470 = 1470.
- 2 x 735 = 1470.
- 3 x 490 = 1470.
- 5 x 294 = 1470.
- 6 x 245 = 1470.
- 7 x 210 = 1470.
- 10 x 147 = 1470.
- 14 x 105 = 1470.
What is the divisible of 6123?
The number 6,123 is divisible by 3….
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Is 1381 divisible by any number?
If 1381 were not a prime number, then it would be divisible by at least one prime number less than or equal to √1381. Since 1381 cannot be divided evenly by 2, 3, 5, 7, 11, 13, 17, 19, 23, 29, 31, or 37, we know that 1381 is a prime number.
What is the smallest number of 1125 divisible by 3?
Expert Answer:
- Prime factorisation of 1125 is as follows:
- 1125 = 3 x 3 x 5 x 5 x 5 = 32 x 53
- When we divide this by 32 i.e. 9, we get 53 which is the perfect cube.
- Hence, the smallest number by dividing which, 1125 becomes a perfecr cube is 9.
Is 107 composite or prime?
prime number
In mathematics 107 is the 28th prime number. The next prime is 109, with which it comprises a twin prime, making 107 a Chen prime.
What are the factors of 1890?
Factors of 1890
- All Factors of 1890: 1, 2, 3, 5, 6, 7, 9, 10, 14, 15, 18, 21, 27, 30, 35, 42, 45, 54, 63, 70, 90, 105, 126, 135, 189, 210, 270, 315, 378, 630, 945 and 1890.
- Prime Factors of 1890: 2, 3, 5, 7.
- Prime Factorization of 1890: 21 × 33 × 51 × 71
- Sum of Factors of 1890: 5760.
What is the LCM of 1125?
The factors of 1125 are 1, 3, 5, 9, 15, 25, 45, 75, 125, 225, 375, 1125 and factors of 727 are 1, 727. Therefore, the Least Common Multiple (LCM) of 1125 and 727 is 817875 and Highest Common Factor (HCF) of 1125 and 727 is 1. Example 3: Find if 1, 3, 25, 125, 225, 621 and 1125 are factors of 1125.
What is the prime factor of 1125?
Prime factorization: 1125 = 3 × 3 × 5 × 5 × 5, which can be written 1125 = 3² × 5³ The exponents in the prime factorization are 2 and 3.
What is the GCF of 60 and 100?
20
The GCF of 60 and 100 is 20.
How do you write 107 in Roman numerals?
We know that in roman numerals, we write 7 as VII, and 100 as C. Therefore, 107 in roman numerals is written as CVII = C + VII = 100 + 7 = CVII.
What are the factors of 1120?
The factors of 1120 are 1, 2, 4, 5, 7, 8, 10, 14, 16, 20, 28, 32, 35, 40, 56, 70, 80, 112, 140, 160, 224, 280, 560, 1120 and factors of 28 are 1, 2, 4, 7, 14, 28.
What is the LCM 1125 and 1350?
6750
The LCM of 1125,1350 is the result of multiplying all prime factors the greatest number of times they occur in either number. The LCM of 1125,1350 is 2⋅3⋅3⋅3⋅5⋅5⋅5=6750 2 ⋅ 3 ⋅ 3 ⋅ 3 ⋅ 5 ⋅ 5 ⋅ 5 = 6750 .
What are factors of 1225?
Factors of 1225
- All Factors of 1225: 1, 5, 7, 25, 35, 49, 175, 245 and 1225.
- Negative Factors of 1225: -1, -5, -7, -25, -35, -49, -175, -245 and -1225.
- Prime Factors of 1225: 5, 7.
- Prime Factorization of 1225: 52 × 72
- Sum of Factors of 1225: 1767.
What is the LCM of 1225?
Answer: LCM of 1225 and 1243 is 1522675. 2. What are the Factors of 1225? Answer: Factors of 1225 are 1, 5, 7, 25, 35, 49, 175, 245, 1225.
Is 1125 is a perfect cube?
Is 1125 a Perfect Cube? The number 1125 on prime factorization gives 3 × 3 × 5 × 5 × 5. Here, the prime factor 3 is not in the power of 3. Therefore the cube root of 1125 is irrational, hence 1125 is not a perfect cube.
What is the greatest common divisor of 45 and 33?
So the greatest common factor 33 and 45 is 3.
What is the common factors of 48?
The factors of 48 are 1, 2, 3, 4, 6, 8, 12, 16, 24 and 48.
What is the Arabic number for Cvii?
The Roman numeral CVII corresponds to the Arabic number 107.
What does divisible by mean on a calculator?
Divisible by means ‘A number x is divisible by another number y if x÷ y gives remainder 0’. 2. How do you check divisible by on a calculator? After entering the input value in the input box of the calculator, tap the calculate button, and then it displays the number is divisible by another number as an output along with a detailed explanation.
How do you know if a number is divisible by 11?
Here an easy way to test for divisibility by 11. Take the alternating sum of the digits in the number, read from left to right. If that is divisible by 11, so is the original number. So, for instance, 2728 has alternating sum of digits 2 – 7 + 2 – 8 = -11. Since -11 is divisible by 11, so is 2728.
What is the alternating sum of two numbers divisible by 11?
If that is divisible by 11, so is the original number. So, for instance, 2728 has alternating sum of digits 2 – 7 + 2 – 8 = -11. Since -11 is divisible by 11, so is 2728. Similarly, for 31415, the alternating sum of digits is 3 – 1 + 4 – 1 + 5 = 10. This is not divisible by 11, so neither is 31415.